Question

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Correct option is

Density of orthophosphoric acid $=1.54×0.998=1.54$ g/ml

So mass in $1000$ ml $=1.54×1000=1540$ g.

Gram equivalent weight of orthophosphoric acid$=N−factorMolarmass $ $=398 =32.66$ g-eq.

Gram equivalent weight of orthophosphoric acid$=N−factorMolarmass $ $=398 =32.66$ g-eq.

As the orthophosphoric acid is only $70$% pure

So the weight of orthophosphoric acid $=1540×10070 =1078$ g.

Number of gram equivalents of orthophosphoric acid $=32.661078 =33$

So the weight of orthophosphoric acid $=1540×10070 =1078$ g.

Number of gram equivalents of orthophosphoric acid $=32.661078 =33$

So, the $33$ gram equivalents in $1000$ ml $=33$ N.

as $Normality=(volumeofsolutioninL)(numberofgramequivalents) =33$ N.

Hence, the correct option is $C$

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